- // normally, we didn't count the last token in the loop above - so add it
- // unless the string was empty from the very beginning, in which case it
- // still has 0 (and not 1) tokens
- if ( !m_string.empty() )
+ switch ( m_mode )
+ {
+ case wxTOKEN_RET_EMPTY:
+ case wxTOKEN_RET_DELIMS:
+ // special hack for wxTOKEN_RET_EMPTY: we should return the initial
+ // empty token even if there are only delimiters after it
+ return !m_string.empty() && m_pos == m_string.begin();
+
+ case wxTOKEN_RET_EMPTY_ALL:
+ // special hack for wxTOKEN_RET_EMPTY_ALL: we can know if we had
+ // already returned the trailing empty token after the last
+ // delimiter by examining m_lastDelim: it is set to NUL if we run
+ // up to the end of the string in GetNextToken(), but if it is not
+ // NUL yet we still have this last token to return even if m_pos is
+ // already at m_string.length()
+ return m_pos < m_stringEnd || m_lastDelim != wxT('\0');
+
+ case wxTOKEN_INVALID:
+ case wxTOKEN_DEFAULT:
+ wxFAIL_MSG( wxT("unexpected tokenizer mode") );
+ // fall through
+
+ case wxTOKEN_STRTOK:
+ // never return empty delimiters
+ break;
+ }
+
+ return false;
+}
+
+// count the number of (remaining) tokens in the string
+size_t wxStringTokenizer::CountTokens() const
+{
+ wxCHECK_MSG( IsOk(), 0, wxT("you should call SetString() first") );
+
+ // VZ: this function is IMHO not very useful, so it's probably not very
+ // important if its implementation here is not as efficient as it
+ // could be -- but OTOH like this we're sure to get the correct answer
+ // in all modes
+ wxStringTokenizer tkz(wxString(m_pos, m_stringEnd), m_delims, m_mode);
+
+ size_t count = 0;
+ while ( tkz.HasMoreTokens() )