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34 UnitBezier(double p1x
, double p1y
, double p2x
, double p2y
)
36 // Calculate the polynomial coefficients, implicit first and last control points are (0,0) and (1,1).
38 bx
= 3.0 * (p2x
- p1x
) - cx
;
42 by
= 3.0 * (p2y
- p1y
) - cy
;
46 double sampleCurveX(double t
)
48 // `ax t^3 + bx t^2 + cx t' expanded using Horner's rule.
49 return ((ax
* t
+ bx
) * t
+ cx
) * t
;
52 double sampleCurveY(double t
)
54 return ((ay
* t
+ by
) * t
+ cy
) * t
;
57 double sampleCurveDerivativeX(double t
)
59 return (3.0 * ax
* t
+ 2.0 * bx
) * t
+ cx
;
62 // Given an x value, find a parametric value it came from.
63 double solveCurveX(double x
, double epsilon
)
72 // First try a few iterations of Newton's method -- normally very fast.
73 for (t2
= x
, i
= 0; i
< 8; i
++) {
74 x2
= sampleCurveX(t2
) - x
;
75 if (fabs (x2
) < epsilon
)
77 d2
= sampleCurveDerivativeX(t2
);
83 // Fall back to the bisection method for reliability.
94 x2
= sampleCurveX(t2
);
95 if (fabs(x2
- x
) < epsilon
)
101 t2
= (t1
- t0
) * .5 + t0
;
108 double solve(double x
, double epsilon
)
110 return sampleCurveY(solveCurveX(x
, epsilon
));