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git.saurik.com Git - bison.git/blob - lib/memchr.c
1 /* Copyright (C) 1991,93,96,97,99,2000 Free Software Foundation, Inc.
2 Based on strlen implementation by Torbjorn Granlund (tege@sics.se),
3 with help from Dan Sahlin (dan@sics.se) and
4 commentary by Jim Blandy (jimb@ai.mit.edu);
5 adaptation to memchr suggested by Dick Karpinski (dick@cca.ucsf.edu),
6 and implemented by Roland McGrath (roland@ai.mit.edu).
8 NOTE: The canonical source of this file is maintained with the GNU C Library.
9 Bugs can be reported to bug-glibc@prep.ai.mit.edu.
11 This program is free software; you can redistribute it and/or modify it
12 under the terms of the GNU General Public License as published by the
13 Free Software Foundation; either version 2, or (at your option) any
16 This program is distributed in the hope that it will be useful,
17 but WITHOUT ANY WARRANTY; without even the implied warranty of
18 MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
19 GNU General Public License for more details.
21 You should have received a copy of the GNU General Public License
22 along with this program; if not, write to the Free Software
23 Foundation, Inc., 59 Temple Place - Suite 330, Boston, MA 02111-1307,
31 #if defined (__cplusplus) || (defined (__STDC__) && __STDC__)
32 # define __ptr_t void *
33 #else /* Not C++ or ANSI C. */
34 # define __ptr_t char *
35 #endif /* C++ or ANSI C. */
41 # define reg_char char
44 #if HAVE_STDLIB_H || defined _LIBC
48 #if HAVE_LIMITS_H || defined _LIBC
52 #define LONG_MAX_32_BITS 2147483647
55 # define LONG_MAX LONG_MAX_32_BITS
58 #include <sys/types.h>
59 #if HAVE_BP_SYM_H || defined _LIBC
62 # define BP_SYM(sym) sym
68 /* Search no more than N bytes of S for C. */
75 const unsigned char *char_ptr
;
76 const unsigned long int *longword_ptr
;
77 unsigned long int longword
, magic_bits
, charmask
;
80 c
= (unsigned char) c_in
;
82 /* Handle the first few characters by reading one character at a time.
83 Do this until CHAR_PTR is aligned on a longword boundary. */
84 for (char_ptr
= (const unsigned char *) s
;
85 n
> 0 && ((unsigned long int) char_ptr
86 & (sizeof (longword
) - 1)) != 0;
89 return (__ptr_t
) char_ptr
;
91 /* All these elucidatory comments refer to 4-byte longwords,
92 but the theory applies equally well to 8-byte longwords. */
94 longword_ptr
= (unsigned long int *) char_ptr
;
96 /* Bits 31, 24, 16, and 8 of this number are zero. Call these bits
97 the "holes." Note that there is a hole just to the left of
98 each byte, with an extra at the end:
100 bits: 01111110 11111110 11111110 11111111
101 bytes: AAAAAAAA BBBBBBBB CCCCCCCC DDDDDDDD
103 The 1-bits make sure that carries propagate to the next 0-bit.
104 The 0-bits provide holes for carries to fall into. */
106 if (sizeof (longword
) != 4 && sizeof (longword
) != 8)
109 #if LONG_MAX <= LONG_MAX_32_BITS
110 magic_bits
= 0x7efefeff;
112 magic_bits
= ((unsigned long int) 0x7efefefe << 32) | 0xfefefeff;
115 /* Set up a longword, each of whose bytes is C. */
116 charmask
= c
| (c
<< 8);
117 charmask
|= charmask
<< 16;
118 #if LONG_MAX > LONG_MAX_32_BITS
119 charmask
|= charmask
<< 32;
122 /* Instead of the traditional loop which tests each character,
123 we will test a longword at a time. The tricky part is testing
124 if *any of the four* bytes in the longword in question are zero. */
125 while (n
>= sizeof (longword
))
127 /* We tentatively exit the loop if adding MAGIC_BITS to
128 LONGWORD fails to change any of the hole bits of LONGWORD.
130 1) Is this safe? Will it catch all the zero bytes?
131 Suppose there is a byte with all zeros. Any carry bits
132 propagating from its left will fall into the hole at its
133 least significant bit and stop. Since there will be no
134 carry from its most significant bit, the LSB of the
135 byte to the left will be unchanged, and the zero will be
138 2) Is this worthwhile? Will it ignore everything except
139 zero bytes? Suppose every byte of LONGWORD has a bit set
140 somewhere. There will be a carry into bit 8. If bit 8
141 is set, this will carry into bit 16. If bit 8 is clear,
142 one of bits 9-15 must be set, so there will be a carry
143 into bit 16. Similarly, there will be a carry into bit
144 24. If one of bits 24-30 is set, there will be a carry
145 into bit 31, so all of the hole bits will be changed.
147 The one misfire occurs when bits 24-30 are clear and bit
148 31 is set; in this case, the hole at bit 31 is not
149 changed. If we had access to the processor carry flag,
150 we could close this loophole by putting the fourth hole
153 So it ignores everything except 128's, when they're aligned
156 3) But wait! Aren't we looking for C, not zero?
157 Good point. So what we do is XOR LONGWORD with a longword,
158 each of whose bytes is C. This turns each byte that is C
161 longword
= *longword_ptr
++ ^ charmask
;
163 /* Add MAGIC_BITS to LONGWORD. */
164 if ((((longword
+ magic_bits
)
166 /* Set those bits that were unchanged by the addition. */
169 /* Look at only the hole bits. If any of the hole bits
170 are unchanged, most likely one of the bytes was a
174 /* Which of the bytes was C? If none of them were, it was
175 a misfire; continue the search. */
177 const unsigned char *cp
= (const unsigned char *) (longword_ptr
- 1);
182 return (__ptr_t
) &cp
[1];
184 return (__ptr_t
) &cp
[2];
186 return (__ptr_t
) &cp
[3];
187 #if LONG_MAX > 2147483647
189 return (__ptr_t
) &cp
[4];
191 return (__ptr_t
) &cp
[5];
193 return (__ptr_t
) &cp
[6];
195 return (__ptr_t
) &cp
[7];
199 n
-= sizeof (longword
);
202 char_ptr
= (const unsigned char *) longword_ptr
;
207 return (__ptr_t
) char_ptr
;
215 weak_alias (__memchr
, BP_SYM (memchr
))