# divisibility. Like we have 3 nodes and need to get 10 slots, we take
# 4 from the first, and 3 from the rest. So the biggest is always the first.
sources = sources.sort{|a,b| b.slots.length <=> a.slots.length}
# divisibility. Like we have 3 nodes and need to get 10 slots, we take
# 4 from the first, and 3 from the rest. So the biggest is always the first.
sources = sources.sort{|a,b| b.slots.length <=> a.slots.length}