+ OP [reduce using rule 1 (exp)]
+ $default reduce using rule 1 (exp)
+
+
+
+]])
+
+AT_CLEANUP
+
+
+
+## -------------------------------- ##
+## Defaulted Conflicted Reduction. ##
+## -------------------------------- ##
+
+# When there are RR conflicts, some rules are disabled. Usually it is
+# simply displayed as:
+#
+# $ reduce using rule 3 (num)
+# $ [reduce using rule 4 (id)]
+#
+# But when `reduce 3' is the default action, we'd produce:
+#
+# $ [reduce using rule 4 (id)]
+# $default reduce using rule 3 (num)
+#
+# In this precise case (a reduction is masked by the default
+# reduction), we make the `reduce 3' explicit:
+#
+# $ reduce using rule 3 (num)
+# $ [reduce using rule 4 (id)]
+# $default reduce using rule 3 (num)
+#
+# Maybe that's not the best display, but then, please propose something
+# else.
+
+AT_SETUP([Defaulted Conflicted Reduction])
+AT_KEYWORDS([report])
+
+AT_DATA([input.y],
+[[%%
+exp: num | id;
+num: '0';
+id : '0';
+%%
+]])
+
+AT_CHECK([bison input.y -o input.c --report=all], 1, [],
+[input.y contains 1 reduce/reduce conflict.
+])
+
+# Check the contents of the report.
+AT_CHECK([cat input.output], [],
+[[State 1 contains 1 reduce/reduce conflict.
+
+
+Grammar
+
+ 0 $axiom: exp $
+
+ 1 exp: num
+ 2 | id
+
+ 3 num: '0'
+
+ 4 id: '0'
+
+
+Terminals, with rules where they appear
+
+$ (0) 0
+'0' (48) 3 4
+error (256)
+
+
+Nonterminals, with rules where they appear
+
+$axiom (4)
+ on left: 0
+exp (5)
+ on left: 1 2, on right: 0
+num (6)
+ on left: 3, on right: 1
+id (7)
+ on left: 4, on right: 2
+
+
+state 0
+
+ $axiom -> . exp $ (rule 0)
+ exp -> . num (rule 1)
+ exp -> . id (rule 2)
+ num -> . '0' (rule 3)
+ id -> . '0' (rule 4)
+
+ '0' shift, and go to state 1
+
+ exp go to state 2
+ num go to state 3
+ id go to state 4
+
+
+
+state 1
+
+ num -> '0' . [$] (rule 3)
+ id -> '0' . [$] (rule 4)
+
+ $ reduce using rule 3 (num)
+ $ [reduce using rule 4 (id)]
+ $default reduce using rule 3 (num)
+
+
+
+state 2
+
+ $axiom -> exp . $ (rule 0)
+
+ $ shift, and go to state 5
+
+
+
+state 3
+
+ exp -> num . (rule 1)
+