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1e24cc5b 1This is bison.info, produced by makeinfo version 4.0 from bison.texinfo.
705db0b5
AD
2
3START-INFO-DIR-ENTRY
4* bison: (bison). GNU Project parser generator (yacc replacement).
5END-INFO-DIR-ENTRY
6
7 This file documents the Bison parser generator.
8
9 Copyright (C) 1988, 1989, 1990, 1991, 1992, 1993, 1995, 1998, 1999,
102000 Free Software Foundation, Inc.
11
12 Permission is granted to make and distribute verbatim copies of this
13manual provided the copyright notice and this permission notice are
14preserved on all copies.
15
16 Permission is granted to copy and distribute modified versions of
17this manual under the conditions for verbatim copying, provided also
18that the sections entitled "GNU General Public License" and "Conditions
19for Using Bison" are included exactly as in the original, and provided
20that the entire resulting derived work is distributed under the terms
21of a permission notice identical to this one.
22
23 Permission is granted to copy and distribute translations of this
24manual into another language, under the above conditions for modified
25versions, except that the sections entitled "GNU General Public
26License", "Conditions for Using Bison" and this permission notice may be
27included in translations approved by the Free Software Foundation
28instead of in the original English.
29
30\1f
31File: bison.info, Node: Rpcalc Rules, Next: Rpcalc Lexer, Prev: Rpcalc Decls, Up: RPN Calc
32
33Grammar Rules for `rpcalc'
34--------------------------
35
36 Here are the grammar rules for the reverse polish notation
37calculator.
38
39 input: /* empty */
40 | input line
41 ;
42
43 line: '\n'
44 | exp '\n' { printf ("\t%.10g\n", $1); }
45 ;
46
47 exp: NUM { $$ = $1; }
48 | exp exp '+' { $$ = $1 + $2; }
49 | exp exp '-' { $$ = $1 - $2; }
50 | exp exp '*' { $$ = $1 * $2; }
51 | exp exp '/' { $$ = $1 / $2; }
52 /* Exponentiation */
53 | exp exp '^' { $$ = pow ($1, $2); }
54 /* Unary minus */
55 | exp 'n' { $$ = -$1; }
56 ;
57 %%
58
59 The groupings of the rpcalc "language" defined here are the
60expression (given the name `exp'), the line of input (`line'), and the
61complete input transcript (`input'). Each of these nonterminal symbols
62has several alternate rules, joined by the `|' punctuator which is read
63as "or". The following sections explain what these rules mean.
64
65 The semantics of the language is determined by the actions taken
66when a grouping is recognized. The actions are the C code that appears
67inside braces. *Note Actions::.
68
69 You must specify these actions in C, but Bison provides the means for
70passing semantic values between the rules. In each action, the
71pseudo-variable `$$' stands for the semantic value for the grouping
72that the rule is going to construct. Assigning a value to `$$' is the
73main job of most actions. The semantic values of the components of the
74rule are referred to as `$1', `$2', and so on.
75
76* Menu:
77
78* Rpcalc Input::
79* Rpcalc Line::
80* Rpcalc Expr::
81
82\1f
83File: bison.info, Node: Rpcalc Input, Next: Rpcalc Line, Up: Rpcalc Rules
84
85Explanation of `input'
86......................
87
88 Consider the definition of `input':
89
90 input: /* empty */
91 | input line
92 ;
93
94 This definition reads as follows: "A complete input is either an
95empty string, or a complete input followed by an input line". Notice
96that "complete input" is defined in terms of itself. This definition
97is said to be "left recursive" since `input' appears always as the
98leftmost symbol in the sequence. *Note Recursive Rules: Recursion.
99
100 The first alternative is empty because there are no symbols between
101the colon and the first `|'; this means that `input' can match an empty
102string of input (no tokens). We write the rules this way because it is
103legitimate to type `Ctrl-d' right after you start the calculator. It's
104conventional to put an empty alternative first and write the comment
105`/* empty */' in it.
106
107 The second alternate rule (`input line') handles all nontrivial
108input. It means, "After reading any number of lines, read one more
109line if possible." The left recursion makes this rule into a loop.
110Since the first alternative matches empty input, the loop can be
111executed zero or more times.
112
113 The parser function `yyparse' continues to process input until a
114grammatical error is seen or the lexical analyzer says there are no more
115input tokens; we will arrange for the latter to happen at end of file.
116
117\1f
118File: bison.info, Node: Rpcalc Line, Next: Rpcalc Expr, Prev: Rpcalc Input, Up: Rpcalc Rules
119
120Explanation of `line'
121.....................
122
123 Now consider the definition of `line':
124
125 line: '\n'
126 | exp '\n' { printf ("\t%.10g\n", $1); }
127 ;
128
129 The first alternative is a token which is a newline character; this
130means that rpcalc accepts a blank line (and ignores it, since there is
131no action). The second alternative is an expression followed by a
132newline. This is the alternative that makes rpcalc useful. The
133semantic value of the `exp' grouping is the value of `$1' because the
134`exp' in question is the first symbol in the alternative. The action
135prints this value, which is the result of the computation the user
136asked for.
137
138 This action is unusual because it does not assign a value to `$$'.
139As a consequence, the semantic value associated with the `line' is
140uninitialized (its value will be unpredictable). This would be a bug if
141that value were ever used, but we don't use it: once rpcalc has printed
142the value of the user's input line, that value is no longer needed.
143
144\1f
145File: bison.info, Node: Rpcalc Expr, Prev: Rpcalc Line, Up: Rpcalc Rules
146
147Explanation of `expr'
148.....................
149
150 The `exp' grouping has several rules, one for each kind of
151expression. The first rule handles the simplest expressions: those
152that are just numbers. The second handles an addition-expression,
153which looks like two expressions followed by a plus-sign. The third
154handles subtraction, and so on.
155
156 exp: NUM
157 | exp exp '+' { $$ = $1 + $2; }
158 | exp exp '-' { $$ = $1 - $2; }
159 ...
160 ;
161
162 We have used `|' to join all the rules for `exp', but we could
163equally well have written them separately:
164
165 exp: NUM ;
166 exp: exp exp '+' { $$ = $1 + $2; } ;
167 exp: exp exp '-' { $$ = $1 - $2; } ;
168 ...
169
170 Most of the rules have actions that compute the value of the
171expression in terms of the value of its parts. For example, in the
172rule for addition, `$1' refers to the first component `exp' and `$2'
173refers to the second one. The third component, `'+'', has no meaningful
174associated semantic value, but if it had one you could refer to it as
175`$3'. When `yyparse' recognizes a sum expression using this rule, the
176sum of the two subexpressions' values is produced as the value of the
177entire expression. *Note Actions::.
178
179 You don't have to give an action for every rule. When a rule has no
180action, Bison by default copies the value of `$1' into `$$'. This is
181what happens in the first rule (the one that uses `NUM').
182
183 The formatting shown here is the recommended convention, but Bison
184does not require it. You can add or change whitespace as much as you
185wish. For example, this:
186
187 exp : NUM | exp exp '+' {$$ = $1 + $2; } | ...
188
189means the same thing as this:
190
191 exp: NUM
192 | exp exp '+' { $$ = $1 + $2; }
193 | ...
194
195The latter, however, is much more readable.
196
197\1f
198File: bison.info, Node: Rpcalc Lexer, Next: Rpcalc Main, Prev: Rpcalc Rules, Up: RPN Calc
199
200The `rpcalc' Lexical Analyzer
201-----------------------------
202
203 The lexical analyzer's job is low-level parsing: converting
204characters or sequences of characters into tokens. The Bison parser
205gets its tokens by calling the lexical analyzer. *Note The Lexical
206Analyzer Function `yylex': Lexical.
207
208 Only a simple lexical analyzer is needed for the RPN calculator.
209This lexical analyzer skips blanks and tabs, then reads in numbers as
210`double' and returns them as `NUM' tokens. Any other character that
211isn't part of a number is a separate token. Note that the token-code
212for such a single-character token is the character itself.
213
214 The return value of the lexical analyzer function is a numeric code
215which represents a token type. The same text used in Bison rules to
216stand for this token type is also a C expression for the numeric code
217for the type. This works in two ways. If the token type is a
218character literal, then its numeric code is the ASCII code for that
219character; you can use the same character literal in the lexical
220analyzer to express the number. If the token type is an identifier,
221that identifier is defined by Bison as a C macro whose definition is
222the appropriate number. In this example, therefore, `NUM' becomes a
223macro for `yylex' to use.
224
225 The semantic value of the token (if it has one) is stored into the
226global variable `yylval', which is where the Bison parser will look for
227it. (The C data type of `yylval' is `YYSTYPE', which was defined at
228the beginning of the grammar; *note Declarations for `rpcalc': Rpcalc
229Decls..)
230
231 A token type code of zero is returned if the end-of-file is
232encountered. (Bison recognizes any nonpositive value as indicating the
233end of the input.)
234
235 Here is the code for the lexical analyzer:
236
237 /* Lexical analyzer returns a double floating point
238 number on the stack and the token NUM, or the ASCII
239 character read if not a number. Skips all blanks
240 and tabs, returns 0 for EOF. */
241
242 #include <ctype.h>
243
244 int
245 yylex (void)
246 {
247 int c;
248
249 /* skip white space */
250 while ((c = getchar ()) == ' ' || c == '\t')
251 ;
252 /* process numbers */
253 if (c == '.' || isdigit (c))
254 {
255 ungetc (c, stdin);
256 scanf ("%lf", &yylval);
257 return NUM;
258 }
259 /* return end-of-file */
260 if (c == EOF)
261 return 0;
262 /* return single chars */
263 return c;
264 }
265
266\1f
267File: bison.info, Node: Rpcalc Main, Next: Rpcalc Error, Prev: Rpcalc Lexer, Up: RPN Calc
268
269The Controlling Function
270------------------------
271
272 In keeping with the spirit of this example, the controlling function
273is kept to the bare minimum. The only requirement is that it call
274`yyparse' to start the process of parsing.
275
276 int
277 main (void)
278 {
279 return yyparse ();
280 }
281
282\1f
283File: bison.info, Node: Rpcalc Error, Next: Rpcalc Gen, Prev: Rpcalc Main, Up: RPN Calc
284
285The Error Reporting Routine
286---------------------------
287
288 When `yyparse' detects a syntax error, it calls the error reporting
289function `yyerror' to print an error message (usually but not always
290`"parse error"'). It is up to the programmer to supply `yyerror'
291(*note Parser C-Language Interface: Interface.), so here is the
292definition we will use:
293
294 #include <stdio.h>
295
296 void
297 yyerror (const char *s) /* Called by yyparse on error */
298 {
299 printf ("%s\n", s);
300 }
301
302 After `yyerror' returns, the Bison parser may recover from the error
303and continue parsing if the grammar contains a suitable error rule
304(*note Error Recovery::). Otherwise, `yyparse' returns nonzero. We
305have not written any error rules in this example, so any invalid input
306will cause the calculator program to exit. This is not clean behavior
307for a real calculator, but it is adequate for the first example.
308
309\1f
310File: bison.info, Node: Rpcalc Gen, Next: Rpcalc Compile, Prev: Rpcalc Error, Up: RPN Calc
311
312Running Bison to Make the Parser
313--------------------------------
314
315 Before running Bison to produce a parser, we need to decide how to
316arrange all the source code in one or more source files. For such a
317simple example, the easiest thing is to put everything in one file. The
318definitions of `yylex', `yyerror' and `main' go at the end, in the
319"additional C code" section of the file (*note The Overall Layout of a
320Bison Grammar: Grammar Layout.).
321
322 For a large project, you would probably have several source files,
323and use `make' to arrange to recompile them.
324
325 With all the source in a single file, you use the following command
326to convert it into a parser file:
327
328 bison FILE_NAME.y
329
330In this example the file was called `rpcalc.y' (for "Reverse Polish
331CALCulator"). Bison produces a file named `FILE_NAME.tab.c', removing
332the `.y' from the original file name. The file output by Bison contains
333the source code for `yyparse'. The additional functions in the input
334file (`yylex', `yyerror' and `main') are copied verbatim to the output.
335
336\1f
337File: bison.info, Node: Rpcalc Compile, Prev: Rpcalc Gen, Up: RPN Calc
338
339Compiling the Parser File
340-------------------------
341
342 Here is how to compile and run the parser file:
343
344 # List files in current directory.
345 % ls
346 rpcalc.tab.c rpcalc.y
347
348 # Compile the Bison parser.
349 # `-lm' tells compiler to search math library for `pow'.
350 % cc rpcalc.tab.c -lm -o rpcalc
351
352 # List files again.
353 % ls
354 rpcalc rpcalc.tab.c rpcalc.y
355
356 The file `rpcalc' now contains the executable code. Here is an
357example session using `rpcalc'.
358
359 % rpcalc
360 4 9 +
361 13
362 3 7 + 3 4 5 *+-
363 -13
364 3 7 + 3 4 5 * + - n Note the unary minus, `n'
365 13
366 5 6 / 4 n +
367 -3.166666667
368 3 4 ^ Exponentiation
369 81
370 ^D End-of-file indicator
371 %
372
373\1f
374File: bison.info, Node: Infix Calc, Next: Simple Error Recovery, Prev: RPN Calc, Up: Examples
375
376Infix Notation Calculator: `calc'
377=================================
378
379 We now modify rpcalc to handle infix operators instead of postfix.
380Infix notation involves the concept of operator precedence and the need
381for parentheses nested to arbitrary depth. Here is the Bison code for
382`calc.y', an infix desk-top calculator.
383
384 /* Infix notation calculator--calc */
385
386 %{
387 #define YYSTYPE double
388 #include <math.h>
389 %}
390
391 /* BISON Declarations */
392 %token NUM
393 %left '-' '+'
394 %left '*' '/'
395 %left NEG /* negation--unary minus */
396 %right '^' /* exponentiation */
397
398 /* Grammar follows */
399 %%
400 input: /* empty string */
401 | input line
402 ;
403
404 line: '\n'
405 | exp '\n' { printf ("\t%.10g\n", $1); }
406 ;
407
408 exp: NUM { $$ = $1; }
409 | exp '+' exp { $$ = $1 + $3; }
410 | exp '-' exp { $$ = $1 - $3; }
411 | exp '*' exp { $$ = $1 * $3; }
412 | exp '/' exp { $$ = $1 / $3; }
413 | '-' exp %prec NEG { $$ = -$2; }
414 | exp '^' exp { $$ = pow ($1, $3); }
415 | '(' exp ')' { $$ = $2; }
416 ;
417 %%
418
419The functions `yylex', `yyerror' and `main' can be the same as before.
420
421 There are two important new features shown in this code.
422
423 In the second section (Bison declarations), `%left' declares token
424types and says they are left-associative operators. The declarations
425`%left' and `%right' (right associativity) take the place of `%token'
426which is used to declare a token type name without associativity.
427(These tokens are single-character literals, which ordinarily don't
428need to be declared. We declare them here to specify the
429associativity.)
430
431 Operator precedence is determined by the line ordering of the
432declarations; the higher the line number of the declaration (lower on
433the page or screen), the higher the precedence. Hence, exponentiation
434has the highest precedence, unary minus (`NEG') is next, followed by
435`*' and `/', and so on. *Note Operator Precedence: Precedence.
436
437 The other important new feature is the `%prec' in the grammar section
438for the unary minus operator. The `%prec' simply instructs Bison that
439the rule `| '-' exp' has the same precedence as `NEG'--in this case the
440next-to-highest. *Note Context-Dependent Precedence: Contextual
441Precedence.
442
443 Here is a sample run of `calc.y':
444
445 % calc
446 4 + 4.5 - (34/(8*3+-3))
447 6.880952381
448 -56 + 2
449 -54
450 3 ^ 2
451 9
452
453\1f
454File: bison.info, Node: Simple Error Recovery, Next: Multi-function Calc, Prev: Infix Calc, Up: Examples
455
456Simple Error Recovery
457=====================
458
459 Up to this point, this manual has not addressed the issue of "error
460recovery"--how to continue parsing after the parser detects a syntax
461error. All we have handled is error reporting with `yyerror'. Recall
462that by default `yyparse' returns after calling `yyerror'. This means
463that an erroneous input line causes the calculator program to exit.
464Now we show how to rectify this deficiency.
465
466 The Bison language itself includes the reserved word `error', which
467may be included in the grammar rules. In the example below it has been
468added to one of the alternatives for `line':
469
470 line: '\n'
471 | exp '\n' { printf ("\t%.10g\n", $1); }
472 | error '\n' { yyerrok; }
473 ;
474
475 This addition to the grammar allows for simple error recovery in the
476event of a parse error. If an expression that cannot be evaluated is
477read, the error will be recognized by the third rule for `line', and
478parsing will continue. (The `yyerror' function is still called upon to
479print its message as well.) The action executes the statement
480`yyerrok', a macro defined automatically by Bison; its meaning is that
481error recovery is complete (*note Error Recovery::). Note the
482difference between `yyerrok' and `yyerror'; neither one is a misprint.
483
484 This form of error recovery deals with syntax errors. There are
485other kinds of errors; for example, division by zero, which raises an
486exception signal that is normally fatal. A real calculator program
487must handle this signal and use `longjmp' to return to `main' and
488resume parsing input lines; it would also have to discard the rest of
489the current line of input. We won't discuss this issue further because
490it is not specific to Bison programs.
491
492\1f
493File: bison.info, Node: Multi-function Calc, Next: Exercises, Prev: Simple Error Recovery, Up: Examples
494
495Multi-Function Calculator: `mfcalc'
496===================================
497
498 Now that the basics of Bison have been discussed, it is time to move
499on to a more advanced problem. The above calculators provided only five
500functions, `+', `-', `*', `/' and `^'. It would be nice to have a
501calculator that provides other mathematical functions such as `sin',
502`cos', etc.
503
504 It is easy to add new operators to the infix calculator as long as
505they are only single-character literals. The lexical analyzer `yylex'
506passes back all nonnumber characters as tokens, so new grammar rules
507suffice for adding a new operator. But we want something more
508flexible: built-in functions whose syntax has this form:
509
510 FUNCTION_NAME (ARGUMENT)
511
512At the same time, we will add memory to the calculator, by allowing you
513to create named variables, store values in them, and use them later.
514Here is a sample session with the multi-function calculator:
515
516 % mfcalc
517 pi = 3.141592653589
518 3.1415926536
519 sin(pi)
520 0.0000000000
521 alpha = beta1 = 2.3
522 2.3000000000
523 alpha
524 2.3000000000
525 ln(alpha)
526 0.8329091229
527 exp(ln(beta1))
528 2.3000000000
529 %
530
531 Note that multiple assignment and nested function calls are
532permitted.
533
534* Menu:
535
536* Decl: Mfcalc Decl. Bison declarations for multi-function calculator.
537* Rules: Mfcalc Rules. Grammar rules for the calculator.
538* Symtab: Mfcalc Symtab. Symbol table management subroutines.
539
540\1f
541File: bison.info, Node: Mfcalc Decl, Next: Mfcalc Rules, Up: Multi-function Calc
542
543Declarations for `mfcalc'
544-------------------------
545
546 Here are the C and Bison declarations for the multi-function
547calculator.
548
549 %{
550 #include <math.h> /* For math functions, cos(), sin(), etc. */
551 #include "calc.h" /* Contains definition of `symrec' */
552 %}
553 %union {
554 double val; /* For returning numbers. */
555 symrec *tptr; /* For returning symbol-table pointers */
556 }
557
558 %token <val> NUM /* Simple double precision number */
559 %token <tptr> VAR FNCT /* Variable and Function */
560 %type <val> exp
561
562 %right '='
563 %left '-' '+'
564 %left '*' '/'
565 %left NEG /* Negation--unary minus */
566 %right '^' /* Exponentiation */
567
568 /* Grammar follows */
569
570 %%
571
572 The above grammar introduces only two new features of the Bison
573language. These features allow semantic values to have various data
574types (*note More Than One Value Type: Multiple Types.).
575
576 The `%union' declaration specifies the entire list of possible types;
577this is instead of defining `YYSTYPE'. The allowable types are now
578double-floats (for `exp' and `NUM') and pointers to entries in the
579symbol table. *Note The Collection of Value Types: Union Decl.
580
581 Since values can now have various types, it is necessary to
582associate a type with each grammar symbol whose semantic value is used.
583These symbols are `NUM', `VAR', `FNCT', and `exp'. Their declarations
584are augmented with information about their data type (placed between
585angle brackets).
586
587 The Bison construct `%type' is used for declaring nonterminal
588symbols, just as `%token' is used for declaring token types. We have
589not used `%type' before because nonterminal symbols are normally
590declared implicitly by the rules that define them. But `exp' must be
591declared explicitly so we can specify its value type. *Note
592Nonterminal Symbols: Type Decl.
593
594\1f
595File: bison.info, Node: Mfcalc Rules, Next: Mfcalc Symtab, Prev: Mfcalc Decl, Up: Multi-function Calc
596
597Grammar Rules for `mfcalc'
598--------------------------
599
600 Here are the grammar rules for the multi-function calculator. Most
601of them are copied directly from `calc'; three rules, those which
602mention `VAR' or `FNCT', are new.
603
604 input: /* empty */
605 | input line
606 ;
607
608 line:
609 '\n'
610 | exp '\n' { printf ("\t%.10g\n", $1); }
611 | error '\n' { yyerrok; }
612 ;
613
614 exp: NUM { $$ = $1; }
615 | VAR { $$ = $1->value.var; }
616 | VAR '=' exp { $$ = $3; $1->value.var = $3; }
617 | FNCT '(' exp ')' { $$ = (*($1->value.fnctptr))($3); }
618 | exp '+' exp { $$ = $1 + $3; }
619 | exp '-' exp { $$ = $1 - $3; }
620 | exp '*' exp { $$ = $1 * $3; }
621 | exp '/' exp { $$ = $1 / $3; }
622 | '-' exp %prec NEG { $$ = -$2; }
623 | exp '^' exp { $$ = pow ($1, $3); }
624 | '(' exp ')' { $$ = $2; }
625 ;
626 /* End of grammar */
627 %%
628
629\1f
630File: bison.info, Node: Mfcalc Symtab, Prev: Mfcalc Rules, Up: Multi-function Calc
631
632The `mfcalc' Symbol Table
633-------------------------
634
635 The multi-function calculator requires a symbol table to keep track
636of the names and meanings of variables and functions. This doesn't
637affect the grammar rules (except for the actions) or the Bison
638declarations, but it requires some additional C functions for support.
639
640 The symbol table itself consists of a linked list of records. Its
641definition, which is kept in the header `calc.h', is as follows. It
642provides for either functions or variables to be placed in the table.
643
1e24cc5b
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644 /* Fonctions type. */
645 typedef double (*func_t) (double);
646
705db0b5
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647 /* Data type for links in the chain of symbols. */
648 struct symrec
649 {
650 char *name; /* name of symbol */
651 int type; /* type of symbol: either VAR or FNCT */
1e24cc5b
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652 union
653 {
654 double var; /* value of a VAR */
655 func_t fnctptr; /* value of a FNCT */
705db0b5
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656 } value;
657 struct symrec *next; /* link field */
658 };
659
660 typedef struct symrec symrec;
661
662 /* The symbol table: a chain of `struct symrec'. */
663 extern symrec *sym_table;
664
1e24cc5b
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665 symrec *putsym (const char *, func_t);
666 symrec *getsym (const char *);
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667
668 The new version of `main' includes a call to `init_table', a
669function that initializes the symbol table. Here it is, and
670`init_table' as well:
671
672 #include <stdio.h>
673
674 int
675 main (void)
676 {
677 init_table ();
678 return yyparse ();
679 }
680
681 void
682 yyerror (const char *s) /* Called by yyparse on error */
683 {
684 printf ("%s\n", s);
685 }
686
687 struct init
688 {
689 char *fname;
1e24cc5b 690 double (*fnct)(double);
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691 };
692
693 struct init arith_fncts[] =
694 {
1e24cc5b
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695 "sin", sin,
696 "cos", cos,
705db0b5 697 "atan", atan,
1e24cc5b
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698 "ln", log,
699 "exp", exp,
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700 "sqrt", sqrt,
701 0, 0
702 };
703
704 /* The symbol table: a chain of `struct symrec'. */
1e24cc5b 705 symrec *sym_table = (symrec *) 0;
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706
707 /* Put arithmetic functions in table. */
708 void
709 init_table (void)
710 {
711 int i;
712 symrec *ptr;
713 for (i = 0; arith_fncts[i].fname != 0; i++)
714 {
715 ptr = putsym (arith_fncts[i].fname, FNCT);
716 ptr->value.fnctptr = arith_fncts[i].fnct;
717 }
718 }
719
720 By simply editing the initialization list and adding the necessary
721include files, you can add additional functions to the calculator.
722
723 Two important functions allow look-up and installation of symbols in
724the symbol table. The function `putsym' is passed a name and the type
725(`VAR' or `FNCT') of the object to be installed. The object is linked
726to the front of the list, and a pointer to the object is returned. The
727function `getsym' is passed the name of the symbol to look up. If
728found, a pointer to that symbol is returned; otherwise zero is returned.
729
730 symrec *
731 putsym (char *sym_name, int sym_type)
732 {
733 symrec *ptr;
734 ptr = (symrec *) malloc (sizeof (symrec));
735 ptr->name = (char *) malloc (strlen (sym_name) + 1);
736 strcpy (ptr->name,sym_name);
737 ptr->type = sym_type;
738 ptr->value.var = 0; /* set value to 0 even if fctn. */
739 ptr->next = (struct symrec *)sym_table;
740 sym_table = ptr;
741 return ptr;
742 }
743
744 symrec *
745 getsym (const char *sym_name)
746 {
747 symrec *ptr;
748 for (ptr = sym_table; ptr != (symrec *) 0;
749 ptr = (symrec *)ptr->next)
750 if (strcmp (ptr->name,sym_name) == 0)
751 return ptr;
752 return 0;
753 }
754
755 The function `yylex' must now recognize variables, numeric values,
756and the single-character arithmetic operators. Strings of alphanumeric
757characters with a leading non-digit are recognized as either variables
758or functions depending on what the symbol table says about them.
759
760 The string is passed to `getsym' for look up in the symbol table. If
761the name appears in the table, a pointer to its location and its type
762(`VAR' or `FNCT') is returned to `yyparse'. If it is not already in
763the table, then it is installed as a `VAR' using `putsym'. Again, a
764pointer and its type (which must be `VAR') is returned to `yyparse'.
765
766 No change is needed in the handling of numeric values and arithmetic
767operators in `yylex'.
768
769 #include <ctype.h>
770
771 int
772 yylex (void)
773 {
774 int c;
775
776 /* Ignore whitespace, get first nonwhite character. */
777 while ((c = getchar ()) == ' ' || c == '\t');
778
779 if (c == EOF)
780 return 0;
781
782 /* Char starts a number => parse the number. */
783 if (c == '.' || isdigit (c))
784 {
785 ungetc (c, stdin);
786 scanf ("%lf", &yylval.val);
787 return NUM;
788 }
789
790 /* Char starts an identifier => read the name. */
791 if (isalpha (c))
792 {
793 symrec *s;
794 static char *symbuf = 0;
795 static int length = 0;
796 int i;
797
798 /* Initially make the buffer long enough
799 for a 40-character symbol name. */
800 if (length == 0)
801 length = 40, symbuf = (char *)malloc (length + 1);
802
803 i = 0;
804 do
805 {
806 /* If buffer is full, make it bigger. */
807 if (i == length)
808 {
809 length *= 2;
810 symbuf = (char *)realloc (symbuf, length + 1);
811 }
812 /* Add this character to the buffer. */
813 symbuf[i++] = c;
814 /* Get another character. */
815 c = getchar ();
816 }
817 while (c != EOF && isalnum (c));
818
819 ungetc (c, stdin);
820 symbuf[i] = '\0';
821
822 s = getsym (symbuf);
823 if (s == 0)
824 s = putsym (symbuf, VAR);
825 yylval.tptr = s;
826 return s->type;
827 }
828
829 /* Any other character is a token by itself. */
830 return c;
831 }
832
833 This program is both powerful and flexible. You may easily add new
834functions, and it is a simple job to modify this code to install
835predefined variables such as `pi' or `e' as well.
836
837\1f
838File: bison.info, Node: Exercises, Prev: Multi-function Calc, Up: Examples
839
840Exercises
841=========
842
843 1. Add some new functions from `math.h' to the initialization list.
844
845 2. Add another array that contains constants and their values. Then
846 modify `init_table' to add these constants to the symbol table.
847 It will be easiest to give the constants type `VAR'.
848
849 3. Make the program report an error if the user refers to an
850 uninitialized variable in any way except to store a value in it.
851
852\1f
853File: bison.info, Node: Grammar File, Next: Interface, Prev: Examples, Up: Top
854
855Bison Grammar Files
856*******************
857
858 Bison takes as input a context-free grammar specification and
859produces a C-language function that recognizes correct instances of the
860grammar.
861
862 The Bison grammar input file conventionally has a name ending in
863`.y'.
864
865* Menu:
866
867* Grammar Outline:: Overall layout of the grammar file.
868* Symbols:: Terminal and nonterminal symbols.
869* Rules:: How to write grammar rules.
870* Recursion:: Writing recursive rules.
871* Semantics:: Semantic values and actions.
872* Declarations:: All kinds of Bison declarations are described here.
873* Multiple Parsers:: Putting more than one Bison parser in one program.
874
875\1f
876File: bison.info, Node: Grammar Outline, Next: Symbols, Up: Grammar File
877
878Outline of a Bison Grammar
879==========================
880
881 A Bison grammar file has four main sections, shown here with the
882appropriate delimiters:
883
884 %{
885 C DECLARATIONS
886 %}
887
888 BISON DECLARATIONS
889
890 %%
891 GRAMMAR RULES
892 %%
893
894 ADDITIONAL C CODE
895
896 Comments enclosed in `/* ... */' may appear in any of the sections.
897
898* Menu:
899
900* C Declarations:: Syntax and usage of the C declarations section.
901* Bison Declarations:: Syntax and usage of the Bison declarations section.
902* Grammar Rules:: Syntax and usage of the grammar rules section.
903* C Code:: Syntax and usage of the additional C code section.
904
905\1f
906File: bison.info, Node: C Declarations, Next: Bison Declarations, Up: Grammar Outline
907
908The C Declarations Section
909--------------------------
910
911 The C DECLARATIONS section contains macro definitions and
912declarations of functions and variables that are used in the actions in
913the grammar rules. These are copied to the beginning of the parser
914file so that they precede the definition of `yyparse'. You can use
915`#include' to get the declarations from a header file. If you don't
916need any C declarations, you may omit the `%{' and `%}' delimiters that
917bracket this section.
918
919\1f
920File: bison.info, Node: Bison Declarations, Next: Grammar Rules, Prev: C Declarations, Up: Grammar Outline
921
922The Bison Declarations Section
923------------------------------
924
925 The BISON DECLARATIONS section contains declarations that define
926terminal and nonterminal symbols, specify precedence, and so on. In
927some simple grammars you may not need any declarations. *Note Bison
928Declarations: Declarations.
929
930\1f
931File: bison.info, Node: Grammar Rules, Next: C Code, Prev: Bison Declarations, Up: Grammar Outline
932
933The Grammar Rules Section
934-------------------------
935
936 The "grammar rules" section contains one or more Bison grammar
937rules, and nothing else. *Note Syntax of Grammar Rules: Rules.
938
939 There must always be at least one grammar rule, and the first `%%'
940(which precedes the grammar rules) may never be omitted even if it is
941the first thing in the file.
942
943\1f
944File: bison.info, Node: C Code, Prev: Grammar Rules, Up: Grammar Outline
945
946The Additional C Code Section
947-----------------------------
948
949 The ADDITIONAL C CODE section is copied verbatim to the end of the
950parser file, just as the C DECLARATIONS section is copied to the
951beginning. This is the most convenient place to put anything that you
952want to have in the parser file but which need not come before the
953definition of `yyparse'. For example, the definitions of `yylex' and
954`yyerror' often go here. *Note Parser C-Language Interface: Interface.
955
956 If the last section is empty, you may omit the `%%' that separates it
957from the grammar rules.
958
959 The Bison parser itself contains many static variables whose names
960start with `yy' and many macros whose names start with `YY'. It is a
961good idea to avoid using any such names (except those documented in this
962manual) in the additional C code section of the grammar file.
963
964\1f
965File: bison.info, Node: Symbols, Next: Rules, Prev: Grammar Outline, Up: Grammar File
966
967Symbols, Terminal and Nonterminal
968=================================
969
970 "Symbols" in Bison grammars represent the grammatical classifications
971of the language.
972
973 A "terminal symbol" (also known as a "token type") represents a
974class of syntactically equivalent tokens. You use the symbol in grammar
975rules to mean that a token in that class is allowed. The symbol is
976represented in the Bison parser by a numeric code, and the `yylex'
977function returns a token type code to indicate what kind of token has
978been read. You don't need to know what the code value is; you can use
979the symbol to stand for it.
980
981 A "nonterminal symbol" stands for a class of syntactically equivalent
982groupings. The symbol name is used in writing grammar rules. By
983convention, it should be all lower case.
984
985 Symbol names can contain letters, digits (not at the beginning),
986underscores and periods. Periods make sense only in nonterminals.
987
988 There are three ways of writing terminal symbols in the grammar:
989
990 * A "named token type" is written with an identifier, like an
991 identifier in C. By convention, it should be all upper case. Each
992 such name must be defined with a Bison declaration such as
993 `%token'. *Note Token Type Names: Token Decl.
994
995 * A "character token type" (or "literal character token") is written
996 in the grammar using the same syntax used in C for character
997 constants; for example, `'+'' is a character token type. A
998 character token type doesn't need to be declared unless you need to
999 specify its semantic value data type (*note Data Types of Semantic
1000 Values: Value Type.), associativity, or precedence (*note Operator
1001 Precedence: Precedence.).
1002
1003 By convention, a character token type is used only to represent a
1004 token that consists of that particular character. Thus, the token
1005 type `'+'' is used to represent the character `+' as a token.
1006 Nothing enforces this convention, but if you depart from it, your
1007 program will confuse other readers.
1008
1009 All the usual escape sequences used in character literals in C can
1010 be used in Bison as well, but you must not use the null character
1011 as a character literal because its ASCII code, zero, is the code
1012 `yylex' returns for end-of-input (*note Calling Convention for
1013 `yylex': Calling Convention.).
1014
1015 * A "literal string token" is written like a C string constant; for
1016 example, `"<="' is a literal string token. A literal string token
1017 doesn't need to be declared unless you need to specify its semantic
1018 value data type (*note Value Type::), associativity, or precedence
1019 (*note Precedence::).
1020
1021 You can associate the literal string token with a symbolic name as
1022 an alias, using the `%token' declaration (*note Token
1023 Declarations: Token Decl.). If you don't do that, the lexical
1024 analyzer has to retrieve the token number for the literal string
1025 token from the `yytname' table (*note Calling Convention::).
1026
1027 *WARNING*: literal string tokens do not work in Yacc.
1028
1029 By convention, a literal string token is used only to represent a
1030 token that consists of that particular string. Thus, you should
1031 use the token type `"<="' to represent the string `<=' as a token.
1032 Bison does not enforce this convention, but if you depart from
1033 it, people who read your program will be confused.
1034
1035 All the escape sequences used in string literals in C can be used
1036 in Bison as well. A literal string token must contain two or more
1037 characters; for a token containing just one character, use a
1038 character token (see above).
1039
1040 How you choose to write a terminal symbol has no effect on its
1041grammatical meaning. That depends only on where it appears in rules and
1042on when the parser function returns that symbol.
1043
1044 The value returned by `yylex' is always one of the terminal symbols
1045(or 0 for end-of-input). Whichever way you write the token type in the
1046grammar rules, you write it the same way in the definition of `yylex'.
1047The numeric code for a character token type is simply the ASCII code for
1048the character, so `yylex' can use the identical character constant to
1049generate the requisite code. Each named token type becomes a C macro in
1050the parser file, so `yylex' can use the name to stand for the code.
1051(This is why periods don't make sense in terminal symbols.) *Note
1052Calling Convention for `yylex': Calling Convention.
1053
1054 If `yylex' is defined in a separate file, you need to arrange for the
1055token-type macro definitions to be available there. Use the `-d'
1056option when you run Bison, so that it will write these macro definitions
1057into a separate header file `NAME.tab.h' which you can include in the
1058other source files that need it. *Note Invoking Bison: Invocation.
1059
1060 The symbol `error' is a terminal symbol reserved for error recovery
1061(*note Error Recovery::); you shouldn't use it for any other purpose.
1062In particular, `yylex' should never return this value.
1063
1064\1f
1065File: bison.info, Node: Rules, Next: Recursion, Prev: Symbols, Up: Grammar File
1066
1067Syntax of Grammar Rules
1068=======================
1069
1070 A Bison grammar rule has the following general form:
1071
1072 RESULT: COMPONENTS...
1073 ;
1074
1075where RESULT is the nonterminal symbol that this rule describes, and
1076COMPONENTS are various terminal and nonterminal symbols that are put
1077together by this rule (*note Symbols::).
1078
1079 For example,
1080
1081 exp: exp '+' exp
1082 ;
1083
1084says that two groupings of type `exp', with a `+' token in between, can
1085be combined into a larger grouping of type `exp'.
1086
1087 Whitespace in rules is significant only to separate symbols. You
1088can add extra whitespace as you wish.
1089
1090 Scattered among the components can be ACTIONS that determine the
1091semantics of the rule. An action looks like this:
1092
1093 {C STATEMENTS}
1094
1095Usually there is only one action and it follows the components. *Note
1096Actions::.
1097
1098 Multiple rules for the same RESULT can be written separately or can
1099be joined with the vertical-bar character `|' as follows:
1100
1101 RESULT: RULE1-COMPONENTS...
1102 | RULE2-COMPONENTS...
1103 ...
1104 ;
1105
1106They are still considered distinct rules even when joined in this way.
1107
1108 If COMPONENTS in a rule is empty, it means that RESULT can match the
1109empty string. For example, here is how to define a comma-separated
1110sequence of zero or more `exp' groupings:
1111
1112 expseq: /* empty */
1113 | expseq1
1114 ;
1115
1116 expseq1: exp
1117 | expseq1 ',' exp
1118 ;
1119
1120It is customary to write a comment `/* empty */' in each rule with no
1121components.
1122
1123\1f
1124File: bison.info, Node: Recursion, Next: Semantics, Prev: Rules, Up: Grammar File
1125
1126Recursive Rules
1127===============
1128
1129 A rule is called "recursive" when its RESULT nonterminal appears
1130also on its right hand side. Nearly all Bison grammars need to use
1131recursion, because that is the only way to define a sequence of any
1132number of a particular thing. Consider this recursive definition of a
1133comma-separated sequence of one or more expressions:
1134
1135 expseq1: exp
1136 | expseq1 ',' exp
1137 ;
1138
1139Since the recursive use of `expseq1' is the leftmost symbol in the
1140right hand side, we call this "left recursion". By contrast, here the
1141same construct is defined using "right recursion":
1142
1143 expseq1: exp
1144 | exp ',' expseq1
1145 ;
1146
1147Any kind of sequence can be defined using either left recursion or
1148right recursion, but you should always use left recursion, because it
1149can parse a sequence of any number of elements with bounded stack
1150space. Right recursion uses up space on the Bison stack in proportion
1151to the number of elements in the sequence, because all the elements
1152must be shifted onto the stack before the rule can be applied even
1153once. *Note The Bison Parser Algorithm: Algorithm, for further
1154explanation of this.
1155
1156 "Indirect" or "mutual" recursion occurs when the result of the rule
1157does not appear directly on its right hand side, but does appear in
1158rules for other nonterminals which do appear on its right hand side.
1159
1160 For example:
1161
1162 expr: primary
1163 | primary '+' primary
1164 ;
1165
1166 primary: constant
1167 | '(' expr ')'
1168 ;
1169
1170defines two mutually-recursive nonterminals, since each refers to the
1171other.
1172
1173\1f
1174File: bison.info, Node: Semantics, Next: Declarations, Prev: Recursion, Up: Grammar File
1175
1176Defining Language Semantics
1177===========================
1178
1179 The grammar rules for a language determine only the syntax. The
1180semantics are determined by the semantic values associated with various
1181tokens and groupings, and by the actions taken when various groupings
1182are recognized.
1183
1184 For example, the calculator calculates properly because the value
1185associated with each expression is the proper number; it adds properly
1186because the action for the grouping `X + Y' is to add the numbers
1187associated with X and Y.
1188
1189* Menu:
1190
1191* Value Type:: Specifying one data type for all semantic values.
1192* Multiple Types:: Specifying several alternative data types.
1193* Actions:: An action is the semantic definition of a grammar rule.
1194* Action Types:: Specifying data types for actions to operate on.
1195* Mid-Rule Actions:: Most actions go at the end of a rule.
1196 This says when, why and how to use the exceptional
1197 action in the middle of a rule.
1198
1199\1f
1200File: bison.info, Node: Value Type, Next: Multiple Types, Up: Semantics
1201
1202Data Types of Semantic Values
1203-----------------------------
1204
1205 In a simple program it may be sufficient to use the same data type
1206for the semantic values of all language constructs. This was true in
1207the RPN and infix calculator examples (*note Reverse Polish Notation
1208Calculator: RPN Calc.).
1209
1210 Bison's default is to use type `int' for all semantic values. To
1211specify some other type, define `YYSTYPE' as a macro, like this:
1212
1213 #define YYSTYPE double
1214
1215This macro definition must go in the C declarations section of the
1216grammar file (*note Outline of a Bison Grammar: Grammar Outline.).
1217
1218\1f
1219File: bison.info, Node: Multiple Types, Next: Actions, Prev: Value Type, Up: Semantics
1220
1221More Than One Value Type
1222------------------------
1223
1224 In most programs, you will need different data types for different
1225kinds of tokens and groupings. For example, a numeric constant may
1226need type `int' or `long', while a string constant needs type `char *',
1227and an identifier might need a pointer to an entry in the symbol table.
1228
1229 To use more than one data type for semantic values in one parser,
1230Bison requires you to do two things:
1231
1232 * Specify the entire collection of possible data types, with the
1233 `%union' Bison declaration (*note The Collection of Value Types:
1234 Union Decl.).
1235
1236 * Choose one of those types for each symbol (terminal or
1237 nonterminal) for which semantic values are used. This is done for
1238 tokens with the `%token' Bison declaration (*note Token Type
1239 Names: Token Decl.) and for groupings with the `%type' Bison
1240 declaration (*note Nonterminal Symbols: Type Decl.).
1241
1242\1f
1243File: bison.info, Node: Actions, Next: Action Types, Prev: Multiple Types, Up: Semantics
1244
1245Actions
1246-------
1247
1248 An action accompanies a syntactic rule and contains C code to be
1249executed each time an instance of that rule is recognized. The task of
1250most actions is to compute a semantic value for the grouping built by
1251the rule from the semantic values associated with tokens or smaller
1252groupings.
1253
1254 An action consists of C statements surrounded by braces, much like a
1255compound statement in C. It can be placed at any position in the rule;
1256it is executed at that position. Most rules have just one action at
1257the end of the rule, following all the components. Actions in the
1258middle of a rule are tricky and used only for special purposes (*note
1259Actions in Mid-Rule: Mid-Rule Actions.).
1260
1261 The C code in an action can refer to the semantic values of the
1262components matched by the rule with the construct `$N', which stands for
1263the value of the Nth component. The semantic value for the grouping
1264being constructed is `$$'. (Bison translates both of these constructs
1265into array element references when it copies the actions into the parser
1266file.)
1267
1268 Here is a typical example:
1269
1270 exp: ...
1271 | exp '+' exp
1272 { $$ = $1 + $3; }
1273
1274This rule constructs an `exp' from two smaller `exp' groupings
1275connected by a plus-sign token. In the action, `$1' and `$3' refer to
1276the semantic values of the two component `exp' groupings, which are the
1277first and third symbols on the right hand side of the rule. The sum is
1278stored into `$$' so that it becomes the semantic value of the
1279addition-expression just recognized by the rule. If there were a
1280useful semantic value associated with the `+' token, it could be
1281referred to as `$2'.
1282
1283 If you don't specify an action for a rule, Bison supplies a default:
1284`$$ = $1'. Thus, the value of the first symbol in the rule becomes the
1285value of the whole rule. Of course, the default rule is valid only if
1286the two data types match. There is no meaningful default action for an
1287empty rule; every empty rule must have an explicit action unless the
1288rule's value does not matter.
1289
1290 `$N' with N zero or negative is allowed for reference to tokens and
1291groupings on the stack _before_ those that match the current rule.
1292This is a very risky practice, and to use it reliably you must be
1293certain of the context in which the rule is applied. Here is a case in
1294which you can use this reliably:
1295
1296 foo: expr bar '+' expr { ... }
1297 | expr bar '-' expr { ... }
1298 ;
1299
1300 bar: /* empty */
1301 { previous_expr = $0; }
1302 ;
1303
1304 As long as `bar' is used only in the fashion shown here, `$0' always
1305refers to the `expr' which precedes `bar' in the definition of `foo'.
1306
1307\1f
1308File: bison.info, Node: Action Types, Next: Mid-Rule Actions, Prev: Actions, Up: Semantics
1309
1310Data Types of Values in Actions
1311-------------------------------
1312
1313 If you have chosen a single data type for semantic values, the `$$'
1314and `$N' constructs always have that data type.
1315
1316 If you have used `%union' to specify a variety of data types, then
1317you must declare a choice among these types for each terminal or
1318nonterminal symbol that can have a semantic value. Then each time you
1319use `$$' or `$N', its data type is determined by which symbol it refers
1320to in the rule. In this example,
1321
1322 exp: ...
1323 | exp '+' exp
1324 { $$ = $1 + $3; }
1325
1326`$1' and `$3' refer to instances of `exp', so they all have the data
1327type declared for the nonterminal symbol `exp'. If `$2' were used, it
1328would have the data type declared for the terminal symbol `'+'',
1329whatever that might be.
1330
1331 Alternatively, you can specify the data type when you refer to the
1332value, by inserting `<TYPE>' after the `$' at the beginning of the
1333reference. For example, if you have defined types as shown here:
1334
1335 %union {
1336 int itype;
1337 double dtype;
1338 }
1339
1340then you can write `$<itype>1' to refer to the first subunit of the
1341rule as an integer, or `$<dtype>1' to refer to it as a double.
1342