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1/*
2 * Copyright (c) 2000-2001 Apple Computer, Inc. All rights reserved.
3 *
4 * @APPLE_LICENSE_HEADER_START@
5 *
43866e37 6 * Copyright (c) 1999-2003 Apple Computer, Inc. All Rights Reserved.
0b4e3aa0 7 *
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8 * This file contains Original Code and/or Modifications of Original Code
9 * as defined in and that are subject to the Apple Public Source License
10 * Version 2.0 (the 'License'). You may not use this file except in
11 * compliance with the License. Please obtain a copy of the License at
12 * http://www.opensource.apple.com/apsl/ and read it before using this
13 * file.
14 *
15 * The Original Code and all software distributed under the License are
16 * distributed on an 'AS IS' basis, WITHOUT WARRANTY OF ANY KIND, EITHER
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17 * EXPRESS OR IMPLIED, AND APPLE HEREBY DISCLAIMS ALL SUCH WARRANTIES,
18 * INCLUDING WITHOUT LIMITATION, ANY WARRANTIES OF MERCHANTABILITY,
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19 * FITNESS FOR A PARTICULAR PURPOSE, QUIET ENJOYMENT OR NON-INFRINGEMENT.
20 * Please see the License for the specific language governing rights and
21 * limitations under the License.
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22 *
23 * @APPLE_LICENSE_HEADER_END@
24 */
25;
26;
27; Strlen, optimized for PPC. The routine we use is 2-3x faster
28; then the simple loop which checks each byte for zero.
29; For 0- and 1-byte strings, the simple routine is faster, but
30; only by a few cycles. The algorithm used was adapted from the
31; Mac OS 9 stdCLib strcopy routine, which was originally
32; written by Gary Davidian. It relies on the following rather
33; inobvious but very efficient test:
34;
35; y = dataWord + 0xFEFEFEFF
36; z = ~dataWord & 0x80808080
37; if ( y & z ) = 0 then all bytes in dataWord are non-zero
38;
39; The test maps any non-zero byte to zeros and any zero byte to 0x80,
40; with one exception: 0x01 bytes preceeding the first zero are also
41; mapped to 0x80.
42;
43#include <ppc/asm.h>
44#include <ppc/proc_reg.h>
45;
46; int strlen(ptr)
47;
48;
49
50 .align 5
51 .globl EXT(strlen)
52LEXT(strlen)
53
54 andi. r4,r3,0x03 ; test alignment first
55 mr r9,r3 ; store the original address for later use....
56 bne LalignSource ; align the source addr if not already aligned
57Llentry:
58 lis r5,hi16(0xFEFEFEFF)
59 lis r6,hi16(0x80808080)
60 subi r3,r3,0x04 ; pre-decrement r3 for the lwzu
61 ori r5,r5,lo16(0xFEFEFEFF) ; r5=0xFEFEFEFF
62 ori r6,r6,lo16(0x80808080) ; r6=0x80808080
63
64LLoop:
65 lwzu r8,4(r3) ; get the first 4 bytes and increment address
66 add r4,r5,r8 ; r4= data + 0xFEFEFEFF
67 andc r7,r6,r8 ; r7= ~data & 0x80808080
68 and. r4,r4,r7 ; r4= r4 & r7
69 beq LLoop ; if r4 is zero, then all bytes are non-zero
70
71; Now we know one of the bytes in r8 is zero,
72; we just have to figure out which one.
73; We have mapped 0 bytes to 0x80, and nonzero bytes to 0x00,
74; with one exception:
75; 0x01 bytes preceeding the first zero are also mapped to 0x80.
76; So we have to mask out the 0x80s caused by 0x01s before
77; counting leading zeroes to get the bytes in last word.
78
79 rlwinm r5,r8,7,0,31 ; move 0x01 bits to 0x80 position
80 subf r3,r9,r3 ; start to compute string length
81 andc r4,r4,r5 ; turn off false hits from 0x0100 worst case
82 cntlzw r7,r4 ; now we can count leading 0s
83 srwi r7,r7,3 ; convert 0,8,16,24 to 0,1,2,3
84 add r3,r3,r7 ; add in nonzero bytes in last word
85 blr
86
87; We must align the source address for two reasons: to avoid spurious page
88; faults, and for speed.
89; r4 = low 2 bits of address (1,2, or 3)
90; r3 = address
91; r9 = original address (still same as r3)
92
93LalignSource:
94 lbz r5,0(r3) ; get the first byte...
95 subic. r4,r4,2 ; test for 1, 2 or 3 bytes
96 addi r3,r3,1 ; increment address
97 addi r6,r9,1 ; now r6==r3
98 cmpwi cr1,r5,0 ; zero?
99 beq cr1,Lreturn ; if its zero return zero
100 bgt Llentry ; address is aligned now if low bits were 3
101
102 lbz r5,0(r3) ; get the next byte...
103 addi r3,r3,1 ; increment address
104 cmpwi cr1,r5,0 ; zero?
105 beq cr1,Lreturn ; if its zero return one
106 beq Llentry ; addr is aligned now if low bits were 2
107
108 lbz r5,0(r3) ; get the next byte...
109 addi r3,r3,1 ; increment address
110 cmpwi cr1,r5,0 ; zero?
111 bne cr1,Llentry ; not zero, continue check (now aligned)
112Lreturn:
113 sub r3,r3,r6 ; get string length (0, 1, or 2)
114 blr
115