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1/*
2 * Copyright (c) 1999 Apple Computer, Inc. All rights reserved.
3 *
4 * @APPLE_LICENSE_HEADER_START@
5 *
734aad71 6 * Copyright (c) 1999-2003 Apple Computer, Inc. All Rights Reserved.
e9ce8d39 7 *
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A
8 * This file contains Original Code and/or Modifications of Original Code
9 * as defined in and that are subject to the Apple Public Source License
10 * Version 2.0 (the 'License'). You may not use this file except in
11 * compliance with the License. Please obtain a copy of the License at
12 * http://www.opensource.apple.com/apsl/ and read it before using this
13 * file.
14 *
15 * The Original Code and all software distributed under the License are
16 * distributed on an 'AS IS' basis, WITHOUT WARRANTY OF ANY KIND, EITHER
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17 * EXPRESS OR IMPLIED, AND APPLE HEREBY DISCLAIMS ALL SUCH WARRANTIES,
18 * INCLUDING WITHOUT LIMITATION, ANY WARRANTIES OF MERCHANTABILITY,
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19 * FITNESS FOR A PARTICULAR PURPOSE, QUIET ENJOYMENT OR NON-INFRINGEMENT.
20 * Please see the License for the specific language governing rights and
21 * limitations under the License.
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22 *
23 * @APPLE_LICENSE_HEADER_END@
24 */
25/*
26 * Copyright (c) 1990, 1993
27 * The Regents of the University of California. All rights reserved.
28 *
29 * This code is derived from software contributed to Berkeley by
30 * Chris Torek.
31 *
32 * Redistribution and use in source and binary forms, with or without
33 * modification, are permitted provided that the following conditions
34 * are met:
35 * 1. Redistributions of source code must retain the above copyright
36 * notice, this list of conditions and the following disclaimer.
37 * 2. Redistributions in binary form must reproduce the above copyright
38 * notice, this list of conditions and the following disclaimer in the
39 * documentation and/or other materials provided with the distribution.
40 * 3. All advertising materials mentioning features or use of this software
41 * must display the following acknowledgement:
42 * This product includes software developed by the University of
43 * California, Berkeley and its contributors.
44 * 4. Neither the name of the University nor the names of its contributors
45 * may be used to endorse or promote products derived from this software
46 * without specific prior written permission.
47 *
48 * THIS SOFTWARE IS PROVIDED BY THE REGENTS AND CONTRIBUTORS ``AS IS'' AND
49 * ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
50 * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
51 * ARE DISCLAIMED. IN NO EVENT SHALL THE REGENTS OR CONTRIBUTORS BE LIABLE
52 * FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL
53 * DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS
54 * OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION)
55 * HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT
56 * LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY
57 * OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
58 * SUCH DAMAGE.
59 */
60
61
62#include <stdlib.h> /* div_t */
63
64div_t
65div(num, denom)
66 int num, denom;
67{
68 div_t r;
69
70 r.quot = num / denom;
71 r.rem = num % denom;
72 /*
73 * The ANSI standard says that |r.quot| <= |n/d|, where
74 * n/d is to be computed in infinite precision. In other
75 * words, we should always truncate the quotient towards
76 * 0, never -infinity.
77 *
78 * Machine division and remainer may work either way when
79 * one or both of n or d is negative. If only one is
80 * negative and r.quot has been truncated towards -inf,
81 * r.rem will have the same sign as denom and the opposite
82 * sign of num; if both are negative and r.quot has been
83 * truncated towards -inf, r.rem will be positive (will
84 * have the opposite sign of num). These are considered
85 * `wrong'.
86 *
87 * If both are num and denom are positive, r will always
88 * be positive.
89 *
90 * This all boils down to:
91 * if num >= 0, but r.rem < 0, we got the wrong answer.
92 * In that case, to get the right answer, add 1 to r.quot and
93 * subtract denom from r.rem.
94 */
95 if (num >= 0 && r.rem < 0) {
96 r.quot++;
97 r.rem -= denom;
98 }
99 return (r);
100}