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1/*
2 * Copyright (c) 1999 Apple Computer, Inc. All rights reserved.
3 *
4 * @APPLE_LICENSE_HEADER_START@
5 *
734aad71 6 * Copyright (c) 1999-2003 Apple Computer, Inc. All Rights Reserved.
e9ce8d39 7 *
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8 * This file contains Original Code and/or Modifications of Original Code
9 * as defined in and that are subject to the Apple Public Source License
10 * Version 2.0 (the 'License'). You may not use this file except in
11 * compliance with the License. Please obtain a copy of the License at
12 * http://www.opensource.apple.com/apsl/ and read it before using this
13 * file.
14 *
15 * The Original Code and all software distributed under the License are
16 * distributed on an 'AS IS' basis, WITHOUT WARRANTY OF ANY KIND, EITHER
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17 * EXPRESS OR IMPLIED, AND APPLE HEREBY DISCLAIMS ALL SUCH WARRANTIES,
18 * INCLUDING WITHOUT LIMITATION, ANY WARRANTIES OF MERCHANTABILITY,
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19 * FITNESS FOR A PARTICULAR PURPOSE, QUIET ENJOYMENT OR NON-INFRINGEMENT.
20 * Please see the License for the specific language governing rights and
21 * limitations under the License.
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22 *
23 * @APPLE_LICENSE_HEADER_END@
24 */
25/* Copyright (c) 1992,1997 NeXT Software, Inc. All rights reserved.
26 *
27 * File: libc/gen/ppc/abs.s
28 * Author: Derek B Clegg, NeXT Software, Inc.
29 *
30 * HISTORY
31 * 24-Jan-1997 Umesh Vaishampayan (umeshv@NeXT.com)
32 * Ported to PPC.
33 * 10-Nov-92 Derek B Clegg (dclegg@next.com)
34 * Created.
35 * 13-Jan-93 Derek B Clegg (dclegg@next.com)
36 * Optimized.
37 *
38 * ANSI X3.159-1989:
39 * int abs(int j);
40 *
41 * Description:
42 * The `abs' function computes the absolute value of an integer `j'.
43 * If the result cannot be represented, the behavior is undefined.
44 * Returns:
45 * The `abs' function returns the absolute value.
46 */
47#include <architecture/ppc/asm_help.h>
48#include <architecture/ppc/pseudo_inst.h>
49
50/* We calculate abs(x) as
51 * s = x >> 31;
52 * y = x + s;
53 * return y ^ s;
54 *
55 * If x >= 0, then s = 0, so clearly we return x. On the other hand, if
56 * x < 0, then we may write x as ~z + 1, where z = -x. In this case,
57 * s = -1, so y = x - 1 = ~z, and hence we return -1 ^ (x - 1) = -1 ^ ~z
58 * = z = -x.
59 */
60LEAF(_abs)
61 srawi a1,a0,31
62 add a2,a1,a0
63 xor a0,a2,a1
64 blr
65END(_abs)