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1 /*
2 * The contents of this file are subject to the Netscape Public
3 * License Version 1.1 (the "License"); you may not use this file
4 * except in compliance with the License. You may obtain a copy of
5 * the License at http://www.mozilla.org/NPL/
6 *
7 * Software distributed under the License is distributed on an "AS
8 * IS" basis, WITHOUT WARRANTY OF ANY KIND, either express or
9 * implied. See the License for the specific language governing
10 * rights and limitations under the License.
11 *
12 * The Original Code is mozilla.org code.
13 *
14 * The Initial Developer of the Original Code is Netscape
15 * Communications Corporation. Portions created by Netscape are
16 * Copyright (C) 1998 Netscape Communications Corporation. All
17 * Rights Reserved.
18 *
19 * Contributor(s): pschwartau@netscape.com
20 * Date: 26 November 2000
21 *
22 *
23 *SUMMARY: Passing a RegExp object to a RegExp() constructor.
24 *This test arose from Bugzilla bug 61266. The ECMA3 section is:
25 *
26 * 15.10.4.1 new RegExp(pattern, flags)
27 *
28 * If pattern is an object R whose [[Class]] property is "RegExp" and
29 * flags is undefined, then let P be the pattern used to construct R
30 * and let F be the flags used to construct R. If pattern is an object R
31 * whose [[Class]] property is "RegExp" and flags is not undefined,
32 * then throw a TypeError exception. Otherwise, let P be the empty string
33 * if pattern is undefined and ToString(pattern) otherwise, and let F be
34 * the empty string if flags is undefined and ToString(flags) otherwise.
35 *
36 *
37 *The current test will check the first scenario outlined above:
38 *
39 * "pattern" is itself a RegExp object R
40 * "flags" is undefined
41 *
42 * We check that a new RegExp object obj2 defined from these parameters
43 * is morally the same as the original RegExp object obj1. Of course, they
44 * can't be equal as objects - so we check their enumerable properties...
45 *
46 * In this test, the initial RegExp object obj1 will not include a flag. This test is
47 * identical to test 15.10.4.1-1.js, except that here we use this syntax:
48 *
49 * obj2 = new RegExp(obj1, undefined);
50 *
51 * instead of:
52 *
53 * obj2 = new RegExp(obj1);
54 */
55 //-------------------------------------------------------------------------------------------------
56 var bug = '61266';
57 var summary = 'Passing a RegExp object to a RegExp() constructor';
58 var statprefix = 'Applying RegExp() twice to pattern ';
59 var statsuffix = '; testing property ';
60 var singlequote = "'";
61 var i = -1; var s = '';
62 var obj1 = {}; var obj2 = {};
63 var status = ''; var actual = ''; var expect = ''; var msg = '';
64 var patterns = new Array();
65
66
67 // various regular expressions to try -
68 patterns[0] = '';
69 patterns[1] = 'abc';
70 patterns[2] = '(.*)(3-1)\s\w';
71 patterns[3] = '(.*)(...)\\s\\w';
72 patterns[4] = '[^A-Za-z0-9_]';
73 patterns[5] = '[^\f\n\r\t\v](123.5)([4 - 8]$)';
74
75
76
77 //-------------------------------------------------------------------------------------------------
78 test();
79 //-------------------------------------------------------------------------------------------------
80
81
82 function test()
83 {
84 enterFunc ('test');
85 printBugNumber (bug);
86 printStatus (summary);
87
88 for (i in patterns)
89 {
90 s = patterns[i];
91 status =getStatus(s);
92 obj1 = new RegExp(s);
93 obj2 = new RegExp(obj1, undefined); // see introduction to bug
94
95 for (prop in obj2)
96 {
97 msg = status + quote(prop);
98 actual = obj2[prop];
99 expect = obj1[prop];
100 reportCompare (expect, actual, msg);
101 }
102 }
103
104 exitFunc ('test');
105 }
106
107
108 function getStatus(regexp)
109 {
110 return (statprefix + quote(regexp) + statsuffix);
111 }
112
113
114 function quote(text)
115 {
116 return (singlequote + text + singlequote);
117 }