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1/*
2* The contents of this file are subject to the Netscape Public
3* License Version 1.1 (the "License"); you may not use this file
4* except in compliance with the License. You may obtain a copy of
5* the License at http://www.mozilla.org/NPL/
6*
7* Software distributed under the License is distributed on an "AS
8* IS" basis, WITHOUT WARRANTY OF ANY KIND, either express or
9* implied. See the License for the specific language governing
10* rights and limitations under the License.
11*
12* The Original Code is mozilla.org code.
13*
14* The Initial Developer of the Original Code is Netscape
15* Communications Corporation. Portions created by Netscape are
16* Copyright (C) 1998 Netscape Communications Corporation. All
17* Rights Reserved.
18*
19* Contributor(s): pschwartau@netscape.com
20* Date: 26 November 2000
21*
22*
23*SUMMARY: Passing a RegExp object to a RegExp() constructor.
24*This test arose from Bugzilla bug 61266. The ECMA3 section is:
25*
26* 15.10.4.1 new RegExp(pattern, flags)
27*
28* If pattern is an object R whose [[Class]] property is "RegExp" and
29* flags is undefined, then let P be the pattern used to construct R
30* and let F be the flags used to construct R. If pattern is an object R
31* whose [[Class]] property is "RegExp" and flags is not undefined,
32* then throw a TypeError exception. Otherwise, let P be the empty string
33* if pattern is undefined and ToString(pattern) otherwise, and let F be
34* the empty string if flags is undefined and ToString(flags) otherwise.
35*
36*
37*The current test will check the first scenario outlined above:
38*
39* "pattern" is itself a RegExp object R
40* "flags" is undefined
41*
42* We check that a new RegExp object obj2 defined from these parameters
43* is morally the same as the original RegExp object obj1. Of course, they
44* can't be equal as objects - so we check their enumerable properties...
45*
46* In this test, the initial RegExp object obj1 will not include a flag. The flags
47* parameter for obj2 will be undefined in the sense of not being provided.
48*/
49//-------------------------------------------------------------------------------------------------
50var bug = '61266';
51var summary = 'Passing a RegExp object to a RegExp() constructor';
52var statprefix = 'Applying RegExp() twice to pattern ';
53var statsuffix = '; testing property ';
54var singlequote = "'";
55var i = -1; var s = '';
56var obj1 = {}; var obj2 = {};
57var status = ''; var actual = ''; var expect = ''; var msg = '';
58var patterns = new Array();
59
60
61// various regular expressions to try -
62patterns[0] = '';
63patterns[1] = 'abc';
64patterns[2] = '(.*)(3-1)\s\w';
65patterns[3] = '(.*)(...)\\s\\w';
66patterns[4] = '[^A-Za-z0-9_]';
67patterns[5] = '[^\f\n\r\t\v](123.5)([4 - 8]$)';
68
69
70
71//-------------------------------------------------------------------------------------------------
72test();
73//-------------------------------------------------------------------------------------------------
74
75
76function test()
77{
78 enterFunc ('test');
79 printBugNumber (bug);
80 printStatus (summary);
81
82 for (i in patterns)
83 {
84 s = patterns[i];
85 status =getStatus(s);
86 obj1 = new RegExp(s);
87 obj2 = new RegExp(obj1);
88
89 for (prop in obj2)
90 {
91 msg = status + quote(prop);
92 actual = obj2[prop];
93 expect = obj1[prop];
94 reportCompare (expect, actual, msg);
95 }
96 }
97
98 exitFunc ('test');
99}
100
101
102function getStatus(regexp)
103{
104 return (statprefix + quote(regexp) + statsuffix);
105}
106
107
108function quote(text)
109{
110 return (singlequote + text + singlequote);
111}