+/* Cannot make the following #ifndef U_HIDE_DRAFT_API,
+ it is used to construct other non-internal constants */
+/**
+ * \def UNISTR_OBJECT_SIZE
+ * Desired sizeof(UnicodeString) in bytes.
+ * It should be a multiple of sizeof(pointer) to avoid unusable space for padding.
+ * The object size may want to be a multiple of 16 bytes,
+ * which is a common granularity for heap allocation.
+ *
+ * Any space inside the object beyond sizeof(vtable pointer) + 2
+ * is available for storing short strings inside the object.
+ * The bigger the object, the longer a string that can be stored inside the object,
+ * without additional heap allocation.
+ *
+ * Depending on a platform's pointer size, pointer alignment requirements,
+ * and struct padding, the compiler will usually round up sizeof(UnicodeString)
+ * to 4 * sizeof(pointer) (or 3 * sizeof(pointer) for P128 data models),
+ * to hold the fields for heap-allocated strings.
+ * Such a minimum size also ensures that the object is easily large enough
+ * to hold at least 2 UChars, for one supplementary code point (U16_MAX_LENGTH).
+ *
+ * sizeof(UnicodeString) >= 48 should work for all known platforms.
+ *
+ * For example, on a 64-bit machine where sizeof(vtable pointer) is 8,
+ * sizeof(UnicodeString) = 64 would leave space for
+ * (64 - sizeof(vtable pointer) - 2) / U_SIZEOF_UCHAR = (64 - 8 - 2) / 2 = 27
+ * UChars stored inside the object.
+ *
+ * The minimum object size on a 64-bit machine would be
+ * 4 * sizeof(pointer) = 4 * 8 = 32 bytes,
+ * and the internal buffer would hold up to 11 UChars in that case.
+ *
+ * @see U16_MAX_LENGTH
+ * @draft ICU 56
+ */
+#ifndef UNISTR_OBJECT_SIZE
+# define UNISTR_OBJECT_SIZE 64
+#endif
+