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1/*
2*******************************************************************************
3*
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4* © 2016 and later: Unicode, Inc. and others.
5* License & terms of use: http://www.unicode.org/copyright.html#License
6*
7*******************************************************************************
8*******************************************************************************
9*
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10* Copyright (C) 2002, International Business Machines
11* Corporation and others. All Rights Reserved.
12*
13*******************************************************************************
14*/
15
16#include <stdio.h>
17#include <stdlib.h>
18#include <unicode/ustring.h>
19#include <unicode/ubrk.h>
20
21U_CFUNC int c_main(void);
22
23void printTextRange(UChar* str, int32_t start, int32_t end)
24{
25 char charBuf[1000];
26 UChar savedEndChar;
27
28 savedEndChar = str[end];
29 str[end] = 0;
30 u_austrncpy(charBuf, str+start, sizeof(charBuf)-1);
31 charBuf[sizeof(charBuf)-1]=0;
32 printf("string[%2d..%2d] \"%s\"\n", start, end-1, charBuf);
33 str[end] = savedEndChar;
34}
35
36
37
38/* Print each element in order: */
39void printEachForward( UBreakIterator* boundary, UChar* str) {
40 int32_t end;
41 int32_t start = ubrk_first(boundary);
42 for (end = ubrk_next(boundary); end != UBRK_DONE; start = end, end =
43 ubrk_next(boundary)) {
44 printTextRange(str, start, end );
45 }
46}
47
48
49/* Print each element in reverse order: */
50void printEachBackward( UBreakIterator* boundary, UChar* str) {
51 int32_t start;
52 int32_t end = ubrk_last(boundary);
53 for (start = ubrk_previous(boundary); start != UBRK_DONE; end = start,
54 start =ubrk_previous(boundary)) {
55 printTextRange( str, start, end );
56 }
57}
58
59/* Print first element */
60void printFirst(UBreakIterator* boundary, UChar* str) {
61 int32_t end;
62 int32_t start = ubrk_first(boundary);
63 end = ubrk_next(boundary);
64 printTextRange( str, start, end );
65}
66
67/* Print last element */
68void printLast(UBreakIterator* boundary, UChar* str) {
69 int32_t start;
70 int32_t end = ubrk_last(boundary);
71 start = ubrk_previous(boundary);
72 printTextRange(str, start, end );
73}
74
75/* Print the element at a specified position */
76
77void printAt(UBreakIterator* boundary, int32_t pos , UChar* str) {
78 int32_t start;
79 int32_t end = ubrk_following(boundary, pos);
80 start = ubrk_previous(boundary);
81 printTextRange(str, start, end );
82}
83
84/* Creating and using text boundaries*/
85
86int c_main( void ) {
87 UBreakIterator *boundary;
88 char cStringToExamine[] = "Aaa bbb ccc. Ddd eee fff.";
89 UChar stringToExamine[sizeof(cStringToExamine)+1];
90 UErrorCode status = U_ZERO_ERROR;
91
92 printf("\n\n"
93 "C Boundary Analysis\n"
94 "-------------------\n\n");
95
96 printf("Examining: %s\n", cStringToExamine);
97 u_uastrcpy(stringToExamine, cStringToExamine);
98
99 /*print each sentence in forward and reverse order*/
100 boundary = ubrk_open(UBRK_SENTENCE, "en_us", stringToExamine,
101 -1, &status);
102 if (U_FAILURE(status)) {
103 printf("ubrk_open error: %s\n", u_errorName(status));
104 exit(1);
105 }
106
107 printf("\n----- Sentence Boundaries, forward: -----------\n");
108 printEachForward(boundary, stringToExamine);
109 printf("\n----- Sentence Boundaries, backward: ----------\n");
110 printEachBackward(boundary, stringToExamine);
111 ubrk_close(boundary);
112
113 /*print each word in order*/
114 boundary = ubrk_open(UBRK_WORD, "en_us", stringToExamine,
115 u_strlen(stringToExamine), &status);
116 printf("\n----- Word Boundaries, forward: -----------\n");
117 printEachForward(boundary, stringToExamine);
118 printf("\n----- Word Boundaries, backward: ----------\n");
119 printEachBackward(boundary, stringToExamine);
120 /*print first element*/
121 printf("\n----- first: -------------\n");
122 printFirst(boundary, stringToExamine);
123 /*print last element*/
124 printf("\n----- last: --------------\n");
125 printLast(boundary, stringToExamine);
126 /*print word at charpos 10 */
127 printf("\n----- at pos 10: ---------\n");
128 printAt(boundary, 10 , stringToExamine);
129
130 ubrk_close(boundary);
131
132 printf("\nEnd of C boundary analysis\n");
133 return 0;
134}